AIM:-Consider problem statement given in 2.3, perform following functionalities: a. Initialize X and Y with default value 0. b. Addition of two point is addition of its member X and Y respectively. Provide addPoints function to implement this. i,e, P1=(2, 5), P2=(4, 1), result point (2+4, 5+1)=(6, 6) c. The point which is far from the origin is considered as max point. Implement function which will return point object from given two points. (note: implement using return by reference).

Input:-

#include<iostream>
#include<math.h>
using namespace std;
class xy
{
int x,y,p1x,p2x,p1y,p2y,d1=0,d2=0;
public:
xy(int x1,int y1)
{
x=x1;
y=y1;
}
void setp1(int px1,int py1)
{
p1x=px1;
p1y=py1;
}
void setp2(int px2,int py2)
{
p2x=px2;
p2y=py2;
}
void cal()
{
x=p1x+p2x;
y=p1y+p2y;
}
void display()
{
cout<<"("<<p1x<<","<<p1y<<")"<<"+"<<"("<<p2x<<","<<p2y<<")"<<"="<<"("<<x<<","<<y<<")" ;
cout<<"\n";
}
int cal1()
{
d1=sqrt((p1x-x)*(p1x-x)+(p1y-y)*(p1y-y));
d2=sqrt((p2x-x)*(p2x-x)+(p2y-y)*(p2y-y));
}
void display1()
{
if(d1>d2)
{
cout<<"\np1 is max";
}
else if(d2>d1)
{
cout<<"\np2 is max";
}
else
{
cout<<"\np1=p2";
}
cout<<"\n";
}
};
int main()
{
xy x(0,0);
x.setp1(5,5);
x.setp2(5,5);
x.cal();
x.display();
x.cal1();
x.display1();
return 0;
}
Output:-

**(5,5)+(5,5)=(10,10)**

**p1=p2**

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